\(\int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 (A+B \tan (e+f x)+C \tan ^2(e+f x)) \, dx\) [166]

Optimal result

Integrand size = 45, antiderivative size = 363 \[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\frac {\left (2 a^2 C d^2-a b d (2 c C+B d) (3+m)+b^2 (2+m) \left (2 c^2 C+2 B c d (3+m)+(A-C) d^2 (3+m)\right )\right ) (a+b \tan (e+f x))^{1+m}}{b^3 f (1+m) (2+m) (3+m)}+\frac {(A-i B-C) (c-i d)^2 \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {a+b \tan (e+f x)}{a-i b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (i a+b) f (1+m)}+\frac {(i A-B-i C) (c+i d)^2 \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {a+b \tan (e+f x)}{a+i b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (a+i b) f (1+m)}-\frac {d (2 a C d-b (2 c C+B d (3+m))) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)} \]

[Out]

(2*a^2*C*d^2-a*b*d*(B*d+2*C*c)*(3+m)+b^2*(2+m)*(2*c^2*C+2*B*c*d*(3+m)+(A-C)*d^2*(3+m)))*(a+b*tan(f*x+e))^(1+m)
/b^3/f/(1+m)/(2+m)/(3+m)+1/2*(A-I*B-C)*(c-I*d)^2*hypergeom([1, 1+m],[2+m],(a+b*tan(f*x+e))/(a-I*b))*(a+b*tan(f
*x+e))^(1+m)/(I*a+b)/f/(1+m)+1/2*(I*A-B-I*C)*(c+I*d)^2*hypergeom([1, 1+m],[2+m],(a+b*tan(f*x+e))/(a+I*b))*(a+b
*tan(f*x+e))^(1+m)/(a+I*b)/f/(1+m)-d*(2*C*a*d-b*(2*C*c+B*d*(3+m)))*tan(f*x+e)*(a+b*tan(f*x+e))^(1+m)/b^2/f/(2+
m)/(3+m)+C*(a+b*tan(f*x+e))^(1+m)*(c+d*tan(f*x+e))^2/b/f/(3+m)

Rubi [A] (verified)

Time = 1.19 (sec) , antiderivative size = 360, normalized size of antiderivative = 0.99, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {3728, 3718, 3711, 3620, 3618, 70} \[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\frac {(a+b \tan (e+f x))^{m+1} \left (2 a^2 C d^2-a b d (m+3) (B d+2 c C)+b^2 (m+2) \left (d^2 (m+3) (A-C)+2 B c d (m+3)+2 c^2 C\right )\right )}{b^3 f (m+1) (m+2) (m+3)}+\frac {(c-i d)^2 (A-i B-C) (a+b \tan (e+f x))^{m+1} \operatorname {Hypergeometric2F1}\left (1,m+1,m+2,\frac {a+b \tan (e+f x)}{a-i b}\right )}{2 f (m+1) (b+i a)}+\frac {(c+i d)^2 (i A-B-i C) (a+b \tan (e+f x))^{m+1} \operatorname {Hypergeometric2F1}\left (1,m+1,m+2,\frac {a+b \tan (e+f x)}{a+i b}\right )}{2 f (m+1) (a+i b)}+\frac {d \tan (e+f x) (-2 a C d+b B d (m+3)+2 b c C) (a+b \tan (e+f x))^{m+1}}{b^2 f (m+2) (m+3)}+\frac {C (c+d \tan (e+f x))^2 (a+b \tan (e+f x))^{m+1}}{b f (m+3)} \]

[In]

Int[(a + b*Tan[e + f*x])^m*(c + d*Tan[e + f*x])^2*(A + B*Tan[e + f*x] + C*Tan[e + f*x]^2),x]

[Out]

((2*a^2*C*d^2 - a*b*d*(2*c*C + B*d)*(3 + m) + b^2*(2 + m)*(2*c^2*C + 2*B*c*d*(3 + m) + (A - C)*d^2*(3 + m)))*(
a + b*Tan[e + f*x])^(1 + m))/(b^3*f*(1 + m)*(2 + m)*(3 + m)) + ((A - I*B - C)*(c - I*d)^2*Hypergeometric2F1[1,
1 + m, 2 + m, (a + b*Tan[e + f*x])/(a - I*b)]*(a + b*Tan[e + f*x])^(1 + m))/(2*(I*a + b)*f*(1 + m)) + ((I*A -
B - I*C)*(c + I*d)^2*Hypergeometric2F1[1, 1 + m, 2 + m, (a + b*Tan[e + f*x])/(a + I*b)]*(a + b*Tan[e + f*x])^
(1 + m))/(2*(a + I*b)*f*(1 + m)) + (d*(2*b*c*C - 2*a*C*d + b*B*d*(3 + m))*Tan[e + f*x]*(a + b*Tan[e + f*x])^(1
+ m))/(b^2*f*(2 + m)*(3 + m)) + (C*(a + b*Tan[e + f*x])^(1 + m)*(c + d*Tan[e + f*x])^2)/(b*f*(3 + m))

Rule 70

Int[((a_) + (b_.)*(x_))^(m_)*((c_) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(b*c - a*d)^n*((a + b*x)^(m + 1)/(b^(
n + 1)*(m + 1)))*Hypergeometric2F1[-n, m + 1, m + 2, (-d)*((a + b*x)/(b*c - a*d))], x] /; FreeQ[{a, b, c, d, m
}, x] && NeQ[b*c - a*d, 0] &&  !IntegerQ[m] && IntegerQ[n]

Rule 3618

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[c*(
d/f), Subst[Int[(a + (b/d)*x)^m/(d^2 + c*x), x], x, d*Tan[e + f*x]], x] /; FreeQ[{a, b, c, d, e, f, m}, x] &&
NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && EqQ[c^2 + d^2, 0]

Rule 3620

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)]), x_Symbol] :> Dist[(c
+ I*d)/2, Int[(a + b*Tan[e + f*x])^m*(1 - I*Tan[e + f*x]), x], x] + Dist[(c - I*d)/2, Int[(a + b*Tan[e + f*x]
)^m*(1 + I*Tan[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0]
&& NeQ[c^2 + d^2, 0] &&  !IntegerQ[m]

Rule 3711

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((A_.) + (B_.)*tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (
f_.)*(x_)]^2), x_Symbol] :> Simp[C*((a + b*Tan[e + f*x])^(m + 1)/(b*f*(m + 1))), x] + Int[(a + b*Tan[e + f*x])
^m*Simp[A - C + B*Tan[e + f*x], x], x] /; FreeQ[{a, b, e, f, A, B, C, m}, x] && NeQ[A*b^2 - a*b*B + a^2*C, 0]
&&  !LeQ[m, -1]

Rule 3718

Int[((a_) + (b_.)*tan[(e_.) + (f_.)*(x_)])*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_.)*((A_.) + (B_.)*tan[(e
_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[b*C*Tan[e + f*x]*((c + d*Tan[e + f*x])
^(n + 1)/(d*f*(n + 2))), x] - Dist[1/(d*(n + 2)), Int[(c + d*Tan[e + f*x])^n*Simp[b*c*C - a*A*d*(n + 2) - (A*b
+ a*B - b*C)*d*(n + 2)*Tan[e + f*x] - (a*C*d*(n + 2) - b*(c*C - B*d*(n + 2)))*Tan[e + f*x]^2, x], x], x] /; F
reeQ[{a, b, c, d, e, f, A, B, C, n}, x] && NeQ[b*c - a*d, 0] && NeQ[c^2 + d^2, 0] &&  !LtQ[n, -1]

Rule 3728

Int[((a_.) + (b_.)*tan[(e_.) + (f_.)*(x_)])^(m_.)*((c_.) + (d_.)*tan[(e_.) + (f_.)*(x_)])^(n_)*((A_.) + (B_.)*
tan[(e_.) + (f_.)*(x_)] + (C_.)*tan[(e_.) + (f_.)*(x_)]^2), x_Symbol] :> Simp[C*(a + b*Tan[e + f*x])^m*((c + d
*Tan[e + f*x])^(n + 1)/(d*f*(m + n + 1))), x] + Dist[1/(d*(m + n + 1)), Int[(a + b*Tan[e + f*x])^(m - 1)*(c +
d*Tan[e + f*x])^n*Simp[a*A*d*(m + n + 1) - C*(b*c*m + a*d*(n + 1)) + d*(A*b + a*B - b*C)*(m + n + 1)*Tan[e + f
*x] - (C*m*(b*c - a*d) - b*B*d*(m + n + 1))*Tan[e + f*x]^2, x], x], x] /; FreeQ[{a, b, c, d, e, f, A, B, C, n}
, x] && NeQ[b*c - a*d, 0] && NeQ[a^2 + b^2, 0] && NeQ[c^2 + d^2, 0] && GtQ[m, 0] &&  !(IGtQ[n, 0] && ( !Intege
rQ[m] || (EqQ[c, 0] && NeQ[a, 0])))

Rubi steps \begin{align*} \text {integral}& = \frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}+\frac {\int (a+b \tan (e+f x))^m (c+d \tan (e+f x)) \left (A b c (3+m)-C (2 a d+b c (1+m))+b (B c+(A-C) d) (3+m) \tan (e+f x)+(2 b c C-2 a C d+b B d (3+m)) \tan ^2(e+f x)\right ) \, dx}{b (3+m)} \\ & = \frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}-\frac {\int (a+b \tan (e+f x))^m \left (a d (2 b c C-2 a C d+b B d (3+m))-b c (2+m) (A b c (3+m)-C (2 a d+b c (1+m)))-b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) (2+m) (3+m) \tan (e+f x)-\left (b c (2+m) (2 b c C-2 a C d+b B d (3+m))+d \left (b^2 (B c+(A-C) d) (2+m) (3+m)-a (2 b c C-2 a C d+b B d (3+m))\right )\right ) \tan ^2(e+f x)\right ) \, dx}{b^2 (2+m) (3+m)} \\ & = \frac {\left (2 a^2 C d^2-a b d (2 c C+B d) (3+m)+b^2 (2+m) \left (2 c^2 C+2 B c d (3+m)+(A-C) d^2 (3+m)\right )\right ) (a+b \tan (e+f x))^{1+m}}{b^3 f (1+m) (2+m) (3+m)}+\frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}-\frac {\int (a+b \tan (e+f x))^m \left (-b^2 \left (A c^2-c^2 C-2 B c d-A d^2+C d^2\right ) (2+m) (3+m)-b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) (2+m) (3+m) \tan (e+f x)\right ) \, dx}{b^2 (2+m) (3+m)} \\ & = \frac {\left (2 a^2 C d^2-a b d (2 c C+B d) (3+m)+b^2 (2+m) \left (2 c^2 C+2 B c d (3+m)+(A-C) d^2 (3+m)\right )\right ) (a+b \tan (e+f x))^{1+m}}{b^3 f (1+m) (2+m) (3+m)}+\frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}+\frac {1}{2} \left ((A-i B-C) (c-i d)^2\right ) \int (1+i \tan (e+f x)) (a+b \tan (e+f x))^m \, dx+\frac {1}{2} \left ((A+i B-C) (c+i d)^2\right ) \int (1-i \tan (e+f x)) (a+b \tan (e+f x))^m \, dx \\ & = \frac {\left (2 a^2 C d^2-a b d (2 c C+B d) (3+m)+b^2 (2+m) \left (2 c^2 C+2 B c d (3+m)+(A-C) d^2 (3+m)\right )\right ) (a+b \tan (e+f x))^{1+m}}{b^3 f (1+m) (2+m) (3+m)}+\frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}+\frac {\left ((i A+B-i C) (c-i d)^2\right ) \text {Subst}\left (\int \frac {(a-i b x)^m}{-1+x} \, dx,x,i \tan (e+f x)\right )}{2 f}-\frac {\left (i (A+i B-C) (c+i d)^2\right ) \text {Subst}\left (\int \frac {(a+i b x)^m}{-1+x} \, dx,x,-i \tan (e+f x)\right )}{2 f} \\ & = \frac {\left (2 a^2 C d^2-a b d (2 c C+B d) (3+m)+b^2 (2+m) \left (2 c^2 C+2 B c d (3+m)+(A-C) d^2 (3+m)\right )\right ) (a+b \tan (e+f x))^{1+m}}{b^3 f (1+m) (2+m) (3+m)}-\frac {(i A+B-i C) (c-i d)^2 \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {a+b \tan (e+f x)}{a-i b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (a-i b) f (1+m)}-\frac {(A+i B-C) (c+i d)^2 \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {a+b \tan (e+f x)}{a+i b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (i a-b) f (1+m)}+\frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b^2 f (2+m) (3+m)}+\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)} \\ \end{align*}

Mathematica [A] (verified)

Time = 6.37 (sec) , antiderivative size = 505, normalized size of antiderivative = 1.39 \[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\frac {C (a+b \tan (e+f x))^{1+m} (c+d \tan (e+f x))^2}{b f (3+m)}+\frac {\frac {d (2 b c C-2 a C d+b B d (3+m)) \tan (e+f x) (a+b \tan (e+f x))^{1+m}}{b f (2+m)}-\frac {\frac {\left (-b c (2+m) (2 b c C-2 a C d+b B d (3+m))-d \left (b^2 (B c+(A-C) d) (2+m) (3+m)-a (2 b c C-2 a C d+b B d (3+m))\right )\right ) (a+b \tan (e+f x))^{1+m}}{b f (1+m)}+\frac {i \left (-b^2 \left (A c^2-c^2 C-2 B c d-A d^2+C d^2\right ) (2+m) (3+m)-i b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) (2+m) (3+m)\right ) \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,\frac {-i a-i b \tan (e+f x)}{-i a+b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (a+i b) f (1+m)}-\frac {i \left (-b^2 \left (A c^2-c^2 C-2 B c d-A d^2+C d^2\right ) (2+m) (3+m)+i b^2 \left (2 c (A-C) d+B \left (c^2-d^2\right )\right ) (2+m) (3+m)\right ) \operatorname {Hypergeometric2F1}\left (1,1+m,2+m,-\frac {i a+i b \tan (e+f x)}{-i a-b}\right ) (a+b \tan (e+f x))^{1+m}}{2 (a-i b) f (1+m)}}{b (2+m)}}{b (3+m)} \]

[In]

Integrate[(a + b*Tan[e + f*x])^m*(c + d*Tan[e + f*x])^2*(A + B*Tan[e + f*x] + C*Tan[e + f*x]^2),x]

[Out]

(C*(a + b*Tan[e + f*x])^(1 + m)*(c + d*Tan[e + f*x])^2)/(b*f*(3 + m)) + ((d*(2*b*c*C - 2*a*C*d + b*B*d*(3 + m)
)*Tan[e + f*x]*(a + b*Tan[e + f*x])^(1 + m))/(b*f*(2 + m)) - (((-(b*c*(2 + m)*(2*b*c*C - 2*a*C*d + b*B*d*(3 +
m))) - d*(b^2*(B*c + (A - C)*d)*(2 + m)*(3 + m) - a*(2*b*c*C - 2*a*C*d + b*B*d*(3 + m))))*(a + b*Tan[e + f*x])
^(1 + m))/(b*f*(1 + m)) + ((I/2)*(-(b^2*(A*c^2 - c^2*C - 2*B*c*d - A*d^2 + C*d^2)*(2 + m)*(3 + m)) - I*b^2*(2*
c*(A - C)*d + B*(c^2 - d^2))*(2 + m)*(3 + m))*Hypergeometric2F1[1, 1 + m, 2 + m, ((-I)*a - I*b*Tan[e + f*x])/(
(-I)*a + b)]*(a + b*Tan[e + f*x])^(1 + m))/((a + I*b)*f*(1 + m)) - ((I/2)*(-(b^2*(A*c^2 - c^2*C - 2*B*c*d - A*
d^2 + C*d^2)*(2 + m)*(3 + m)) + I*b^2*(2*c*(A - C)*d + B*(c^2 - d^2))*(2 + m)*(3 + m))*Hypergeometric2F1[1, 1
+ m, 2 + m, -((I*a + I*b*Tan[e + f*x])/((-I)*a - b))]*(a + b*Tan[e + f*x])^(1 + m))/((a - I*b)*f*(1 + m)))/(b*
(2 + m)))/(b*(3 + m))

Maple [F]

\[\int \left (a +b \tan \left (f x +e \right )\right )^{m} \left (c +d \tan \left (f x +e \right )\right )^{2} \left (A +B \tan \left (f x +e \right )+C \tan \left (f x +e \right )^{2}\right )d x\]

[In]

int((a+b*tan(f*x+e))^m*(c+d*tan(f*x+e))^2*(A+B*tan(f*x+e)+C*tan(f*x+e)^2),x)

[Out]

int((a+b*tan(f*x+e))^m*(c+d*tan(f*x+e))^2*(A+B*tan(f*x+e)+C*tan(f*x+e)^2),x)

Fricas [F]

\[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\int { {\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (b \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+b*tan(f*x+e))^m*(c+d*tan(f*x+e))^2*(A+B*tan(f*x+e)+C*tan(f*x+e)^2),x, algorithm="fricas")

[Out]

integral((C*d^2*tan(f*x + e)^4 + (2*C*c*d + B*d^2)*tan(f*x + e)^3 + A*c^2 + (C*c^2 + 2*B*c*d + A*d^2)*tan(f*x
+ e)^2 + (B*c^2 + 2*A*c*d)*tan(f*x + e))*(b*tan(f*x + e) + a)^m, x)

Sympy [F]

\[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\int \left (a + b \tan {\left (e + f x \right )}\right )^{m} \left (c + d \tan {\left (e + f x \right )}\right )^{2} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )\, dx \]

[In]

integrate((a+b*tan(f*x+e))**m*(c+d*tan(f*x+e))**2*(A+B*tan(f*x+e)+C*tan(f*x+e)**2),x)

[Out]

Integral((a + b*tan(e + f*x))**m*(c + d*tan(e + f*x))**2*(A + B*tan(e + f*x) + C*tan(e + f*x)**2), x)

Maxima [F]

\[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\int { {\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (b \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+b*tan(f*x+e))^m*(c+d*tan(f*x+e))^2*(A+B*tan(f*x+e)+C*tan(f*x+e)^2),x, algorithm="maxima")

[Out]

integrate((C*tan(f*x + e)^2 + B*tan(f*x + e) + A)*(d*tan(f*x + e) + c)^2*(b*tan(f*x + e) + a)^m, x)

Giac [F]

\[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\int { {\left (C \tan \left (f x + e\right )^{2} + B \tan \left (f x + e\right ) + A\right )} {\left (d \tan \left (f x + e\right ) + c\right )}^{2} {\left (b \tan \left (f x + e\right ) + a\right )}^{m} \,d x } \]

[In]

integrate((a+b*tan(f*x+e))^m*(c+d*tan(f*x+e))^2*(A+B*tan(f*x+e)+C*tan(f*x+e)^2),x, algorithm="giac")

[Out]

integrate((C*tan(f*x + e)^2 + B*tan(f*x + e) + A)*(d*tan(f*x + e) + c)^2*(b*tan(f*x + e) + a)^m, x)

Mupad [F(-1)]

Timed out. \[ \int (a+b \tan (e+f x))^m (c+d \tan (e+f x))^2 \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx=\int {\left (a+b\,\mathrm {tan}\left (e+f\,x\right )\right )}^m\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^2\,\left (C\,{\mathrm {tan}\left (e+f\,x\right )}^2+B\,\mathrm {tan}\left (e+f\,x\right )+A\right ) \,d x \]

[In]

int((a + b*tan(e + f*x))^m*(c + d*tan(e + f*x))^2*(A + B*tan(e + f*x) + C*tan(e + f*x)^2),x)

[Out]

int((a + b*tan(e + f*x))^m*(c + d*tan(e + f*x))^2*(A + B*tan(e + f*x) + C*tan(e + f*x)^2), x)